Mathc complexes/07p
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c00b.c |
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/* ------------------------------------ */
/* Save as : c00b.c */
/* ------------------------------------ */
#include "w_a.h"
/* ------------------------------------ */
/* ------------------------------------ */
#define RA R5
#define CA C5
#define Cb C1
#define RXY R4
#define CXY C2
/* ------------------------------------ */
/* ------------------------------------ */
int main(void)
{
double xy[R4*(C2*C2)] ={
1, 1,
2, 4,
3, 9,
4, 16 };
double ab[RA*((CA+Cb)*C2)]={
/* x**2 y**2 x y e = +0 */
+1, +0, +0, +0, +0, +1,
+1, +1, +1, +1, +1, +0,
+4, +16, +2, +4, +1, +0,
+9, +81, +3, +9, +1, +0,
+16, +256, +4, +16, +1, +0
};
double **XY = ca_A_mRZ(xy,i_mZ(RXY,CXY));
double **Ab = ca_A_mRZ(ab,i_Abr_Ac_bc_mZ(RA,CA,Cb));
double **A = c_Ab_A_mZ(Ab,i_mZ(RA,CA));
double **b = c_Ab_b_mZ(Ab,i_mZ(RA,Cb));
double **A_T = i_mZ(CA,RA);
double **A_TA = i_mZ(CA,CA); // A_T*A
double **invA_TA = i_mZ(CA,CA); // inv(A_T*A)
double **invA_TAA_T = i_mZ(CA,RA); // inv(A_T*A)*A_T
double **x = i_mZ(CA,Cb); // x = inv(A_T*A)*A_T*b
clrscrn();
printf("\n");
printf(" Find the coefficients a, b, c, d, e, of the curve \n\n");
printf(" ax**2 + by**2 + cx + dy + e = 0 \n\n");
printf(" that passes through these four points.\n\n");
printf(" x y");
p_mRZ(XY,S5,P0,C6);
printf("\n");
printf(" Using the given XY, we obtain this matrix.\n");
printf(" (a = 1. This is my choice)\n\n");
printf(" x**2 y**2 x y ");
p_mRZ(Ab,S7,P2,C6);
stop();
clrscrn();
printf(" A_T :");
p_mRZ(transpose_mZ(A,A_T),S10,P2,C7);
printf(" A_TA :");
p_mRZ(mul_mZ(A_T,A,A_TA),S10,P2,C7);
stop();
clrscrn();
printf(" inv(A_TA) :");
p_mRZ(inv_mZ(A_TA,invA_TA),S10,P4,C7);
printf(" inv(A_TA)*A_T :");
p_mRZ(mul_mZ(invA_TA,A_T,invA_TAA_T),S10,P4,C7);
printf("\n x = inv(A_TA)*A_T*b :");
p_mRZ(mul_mZ(invA_TAA_T,b,x),S10,P4,C7);
stop();
clrscrn();
printf("\n x = inv(A_TA)*A_T*b :");
p_mRZ(x,S10,P2,C7);
printf(" The coefficients a, b, c, d, e, of the curve are : \n\n"
" %+.2fx**2 %+.2fy = 0\n\n"
,x[R1][C1],x[R4][C1]);
stop();
f_mZ(XY);
f_mZ(A);
f_mZ(b);
f_mZ(Ab);
f_mZ(A_T);
f_mZ(A_TA); // A_T*A
f_mZ(invA_TA); // inv(A_T*A)
f_mZ(invA_TAA_T); // inv(A_T*A)*A_T
f_mZ(x);
return 0;
}
/* ------------------------------------ */
/* ------------------------------------ */
Exemple de sortie écran :
Find the coefficients a, b, c, d, e, of the curve
ax**2 + by**2 + cx + dy + e = 0
that passes through these four points.
x y
+1 +1
+2 +4
+3 +9
+4 +16
Using the given XY, we obtain this matrix.
(a = 1. This is my choice)
x**2 y**2 x y
+1.00 +0.00 +0.00 +0.00 +0.00 +1.00
+1.00 +1.00 +1.00 +1.00 +1.00 +0.00
+4.00 +16.00 +2.00 +4.00 +1.00 +0.00
+9.00 +81.00 +3.00 +9.00 +1.00 +0.00
+16.00 +256.00 +4.00 +16.00 +1.00 +0.00
Press return to continue.
A_T :
+1.00 +1.00 +4.00 +9.00 +16.00
+0.00 +1.00 +16.00 +81.00 +256.00
+0.00 +1.00 +2.00 +3.00 +4.00
+0.00 +1.00 +4.00 +9.00 +16.00
+0.00 +1.00 +1.00 +1.00 +1.00
A_TA :
+355.00 +4890.00 +100.00 +354.00 +30.00
+4890.00 +72354.00 +1300.00 +4890.00 +354.00
+100.00 +1300.00 +30.00 +100.00 +10.00
+354.00 +4890.00 +100.00 +354.00 +30.00
+30.00 +354.00 +10.00 +30.00 +4.00
Press return to continue.
inv(A_TA) :
+1.0000 +0.0000 +0.0000 -1.0000 +0.0000
+0.0000 +0.0056 +0.6500 -0.2222 -0.4500
+0.0000 +0.6500 +82.5000 -27.2500 -59.4000
-1.0000 -0.2222 -27.2500 +10.1389 +19.2500
+0.0000 -0.4500 -59.4000 +19.2500 +44.2000
inv(A_TA)*A_T :
+1.0000 +0.0000 +0.0000 +0.0000 +0.0000
+0.0000 -0.0167 +0.0500 -0.0500 +0.0167
+0.0000 -3.5000 +7.0000 -4.5000 +1.0000
-1.0000 +0.9167 -2.2500 +1.7500 -0.4167
+0.0000 +3.6000 -4.8000 +2.8000 -0.6000
x = inv(A_TA)*A_T*b :
+1.0000
+0.0000
+0.0000
-1.0000
+0.0000
Press return to continue.
x = inv(A_TA)*A_T*b :
+1.00
+0.00
+0.00
-1.00
+0.00
The coefficients a, b, c, d, e, of the curve are :
+1.00x**2 -1.00y = 0
Press return to continue.