Mathc initiation/0052
Apparence
Installer et compiler ces fichiers dans votre répertoire de travail.
c0a1.c |
|---|
/* ---------------------------------- */
/* save as c0a1.c */
/* ---------------------------------- */
#include "x_afile.h"
#include "fa.h"
/* ---------------------------------- */
int main(void)
{
double m = 0.;
clrscrn();
printf(" Let S be the part of the graph of z = %s with z >= 0. \n\n", feq);
printf(" Let C be the trace of S on the x-y-plane. \n\n");
printf(" Verify Stokes's theorem for the vector field, \n\n");
printf(" F(x,y,z) = %si %sj %sk\n\n\n\n\n",Meq,Neq,Peq);
printf(" Stoke's theorem. \n\n"
" / // \n"
" | || \n"
" O F.T ds = || (curl F).dS \n"
" | || \n"
" / C // \n"
" S \n\n\n");
stop();
clrscrn();
printf(" // \n"
" || \n"
" || (curl F).dS = \n"
" || \n"
" // \n"
" S \n\n\n"
" with F = Mi + Nj + Pk \n\n"
" (curl F) = [(P_y-N_z)i + (M_z-P_x)j + (N_x-M_y)k] \n\n\n\n"
" dS = (-f_x, -f_y, 1) dA dA = dxdy\n\n");
stop();
clrscrn();
printf(" With the Stokes's theorem you find :\n\n\n");
printf(" F : (x,y,z)-> %si %sj %sk \n\n",Meq,Neq,Peq);
printf(" f : (x,y)-> %s \n\n", feq);
printf(" x1 : (y)-> %s \n", x1eq);
printf(" x0 : (y)-> %s \n\n", x0eq);
printf(" y1 = %+.1f\n y0 = %+.1f\n\n",Y1,Y0);
m = stokes_dxdy( M,N,P,
f,
x0,x1,LOOP,
Y0,Y1,LOOP);
printf(" / y1 / x1(y)\n"
" | | \n"
" | | (curl F).(-f_x, -f_y, 1) dx dy = %.3f\n"
" | | \n"
" / y0 / x0(y)\n\n\n",m);
stop();
return 0;
}
/* ---------------------------------- */
/* ---------------------------------- */
Exemple de sortie écran :
Let S be the part of the graph of z = 9-x**2-y**2 with z >= 0.
Let C be the trace of S on the x-y-plane.
Verify Stokes's theorem for the vector field,
F(x,y,z) = + 3*z*yi + 4*xj + 2*y*xk
Stoke's theorem.
/ //
| ||
O F.T ds = || (curl F).dS
| ||
/ C //
S
Press return to continue.
//
||
|| (curl F).dS =
||
//
S
with F = Mi + Nj + Pk
(curl F) = [(P_y-N_z)i + (M_z-P_x)j + (N_x-M_y)k]
dS = (-f_x, -f_y, 1) dA dA = dxdy
Press return to continue.
With the Stokes's theorem you find :
F : (x,y,z)-> + 3*z*yi + 4*xj + 2*y*xk
f : (x,y)-> 9-x**2-y**2
x1 : (y)-> +sqrt(9-y**2)
x0 : (y)-> -sqrt(9-y**2)
y1 = +3.0
y0 = -3.0
/ y1 / x1(y)
| |
| | (curl F).(-f_x, -f_y, 1) dx dy = 113.006
| |
/ y0 / x0(y)
Press return to continue.