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- point3d p ) { double tplsh; double tmnsh; tplsh = ((*P_f)(p.x+h,p.y,p.z)); tmnsh = ((*P_f)(p.x-h,p.y,p.z)); return(( tplsh-tmnsh)/(2.*h) ); } /*...1 kio (155 mots) - 6 mai 2021 à 08:31
- tplsh; double tmnsh; t = ((*P_f)(p.x , p.y,p.z)); tplsh = ((*P_f)(p.x+h, p.y,p.z)); tmnsh = ((*P_f)(p.x-h, p.y,p.z)); return( (tplsh-2*t+tmnsh)/(h*h)...3 kio (449 mots) - 30 novembre 2023 à 23:07
- the equation\n\n", p.x,p.y,p.z, f_x(p.x,p.y,p.z)); printf(" f_x(%0.2f,%0.2f,%0.2f) = %0.9f" " with the formula \n\n", p.x,p.y,p.z, fxyz_x(f,h,p)); stop();...3 kio (445 mots) - 8 juillet 2023 à 08:20
- the equation\n\n", p.x,p.y,p.z, f_xx(p.x,p.y,p.z)); printf(" f_xx(%0.2f,%0.2f,%0.2f) = %0.9f" " with the formula \n\n", p.x,p.y,p.z, fxyz_xx(f,h,p)); stop();...3 kio (465 mots) - 8 juillet 2023 à 08:21
- the equation\n\n", p.x,p.y,p.z, f_x(p.x,p.y,p.z)); printf(" f_x(%0.2f,%0.2f,%0.2f) = %0.9f" " with the formula \n\n", p.x,p.y,p.z, fxyz_x(f,h,p)); stop();...3 kio (455 mots) - 8 juillet 2023 à 08:20
- the equation\n\n", p.x,p.y,p.z, f_xx(p.x,p.y,p.z)); printf(" f_xx(%0.2f,%0.2f,%0.2f) = %0.9f" " with the formula \n\n", p.x,p.y,p.z, fxyz_xx(f,h,p)); stop();...3 kio (465 mots) - 8 juillet 2023 à 08:21
- %0.2f)\n\n", P.x,P.y,P.z); printf(" satisfy the equation.\n\n"); printf(" f(%0.2f,%0.2f,%0.2f) = %0.9f\n\n\n", P.x,P.y,P.z,f(P.x,P.y,P.z)); printf(" Now...3 kio (424 mots) - 2 décembre 2023 à 21:11
- %0.2f)\n\n", P.x,P.y,P.z); printf(" satisfy the equation.\n\n"); printf(" f(%0.2f,%0.2f,%0.2f) = %0.9f\n\n\n", P.x,P.y,P.z,f(P.x,P.y,P.z)); printf(" Now...3 kio (425 mots) - 2 décembre 2023 à 21:10
- -p.x, fxyz_y(f,h,p), -p.y, fxyz_z(f,h,p), -p.z); printf(" grad(p) = %+.1fi %+.1fj %+.1fk \n\n",u.i,u.j,u.k); printf(" p(%+.1f,%+.1f,%+.1f)\n\n",p.x,p...3 kio (576 mots) - 8 juillet 2023 à 08:23
- -p.x, fxyz_y(f,h,p), -p.y, fxyz_z(f,h,p), -p.z); printf(" grad(p)]p = %+.3fi %+.3fj %+.3fk \n\n",u.i,u.j,u.k); printf(" p(%+.3f,%+.3f,%+.3f)\n\n",p.x,p...3 kio (572 mots) - 8 juillet 2023 à 08:24
- -p.x, fxyz_y(f,h,p), -p.y, fxyz_z(f,h,p), -p.z); printf(" grad(p) = %+.1fi %+.1fj %+.1fk \n\n",u.i,u.j,u.k); printf(" p(%+.1f,%+.1f,%+.1f)\n\n",p.x,p...3 kio (575 mots) - 8 juillet 2023 à 08:24
- printf(" in which f increases most rapidly at p(%+.1f,%+.1f,%+.1f)\n\n\n", p.x,p.y,p.z); printf(" grad f(x,y,z)]p = %+.3fi %+.3fj %+.3fk \n\n\n",u.i,u.j,u.k);...2 kio (319 mots) - 8 juillet 2023 à 08:28
- printf(" in which f decreases most rapidly at p(%+.1f,%+.1f,%+.1f)\n\n\n", p.x,p.y,p.z); printf(" -grad f(x,y,z)]p = %+.3fi %+.3fj %+.3fj \n\n\n",mns_u.i,mns_u...2 kio (329 mots) - 8 juillet 2023 à 08:29
- printf(" Find the gradient of f at the point p(%+.1f,%+.1f,%+.1f)\n\n\n", p.x,p.y,p.z); printf(" grad f(x,y,z)]p = %+.3fi %+.3fj %+.3fk \n\n\n",u.i,u.j,u.k);...2 kio (258 mots) - 28 novembre 2023 à 14:17
- */ pt3d i_pt3d( double a, double b, double c ) { pt3d p; p.x = a; p.y = b; p.z = c; return (p); } /* --------------------------------- */ /*...2 kio (142 mots) - 30 novembre 2023 à 15:11
- Find the directionnal derivative of f at p(%+.1f,%+.1f,%+.1f)\n\n" ,P.x,P.y,P.z); printf(" in the direction from u = %+.1fi %+.1fj %+.1fk \n\n\n" ,u...3 kio (444 mots) - 8 juillet 2023 à 08:27
- Find the directionnal derivative of f at p(%+.1f,%+.1f,%+.1f)\n\n" ,P.x,P.y,P.z); printf(" in the direction from u = %+.1fi %+.1fj %+.1fk \n\n\n" ,u...3 kio (449 mots) - 29 novembre 2023 à 15:51
- = 4.;} x = ((*Pux)(y,z)) + i*(((*Pvx)(y,z))-((*Pux)(y,z)))/nx; p.x = x; p.y = y; p.z = z; M += m * (*P_f)( ((*P_X)(x,y,z)), ((*P_Y)(x,y,z)), ((*P_Z)(x...4 kio (516 mots) - 5 avril 2024 à 13:13
- = 4.;} x = ((*Pux)(y,z)) + i*(((*Pvx)(y,z))-((*Pux)(y,z)))/nx; p.x = x; p.y = y; p.z = z; M += m * (*P_f)( ((*P_X)(x,y,z)), ((*P_Y)(x,y,z)), ((*P_Z)(x...4 kio (516 mots) - 5 avril 2024 à 13:14
- = 4.;} y = ((*Puy)(x,z)) + i*(((*Pvy)(x,z))-((*Puy)(x,z)))/ny; p.x = x; p.y = y; p.z = z; M += m * (*P_f)( ((*P_X)(x,y,z)), ((*P_Y)(x,y,z)), ((*P_Z)(x...4 kio (516 mots) - 5 avril 2024 à 13:14
- – PA PB PC PD PE PF PG PH PI PJ PK PL PM PN PO PP PQ PR PS PT PU PV PW PX PY PZ PAA – Pa-An, Birmanie PAB – Bilaspur, Inde PAC – Aéroport international
- \scriptstyle z^{m}+maz^{m}-1} ; donc + p z m − 1 {\displaystyle \scriptstyle pz^{m}-1} . m a + p = 0 {\displaystyle \scriptstyle ma+p=0} , donc a = − p m
- -P^{3}z_{n}&=\left(Sx_{n+2}-Px_{n+1}\right)^{2}-P\left(Sx_{n+1}-x_{n+2}\right)^{2}\\&=\left(S^{2}-P\right)\left(z_{n+2}-Pz_{n+1}\right)\end{aligned}}}
- pm pn po pp pq pr ps pt pu pv pw px py pz pA pB pC pD pE pF pG pH pI pJ pK pL pM pN pO pP pQ pR pS pT pU pV pW pX pY pZ Pa Pb Pc Pd Pe Pf Pg Ph Pi Pj Pk