Mathc initiation/a490
Apparence
Installer et compiler ces fichiers dans votre répertoire de travail.
c00a.c |
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/* ---------------------------------- */
/* save as c00a.c */
/* ---------------------------------- */
#include "x_afile.h"
#include "fa.h"
/* ---------------------------------- */
int main(void)
{
double i;
clrscrn();
printf(" The Ratio Test. \n\n");
printf(" Let S.a_n be positive-term series. \n\n");
printf(" lim n->oo (a_(n+1)/a_n) = c < 1 The series converge\n");
printf(" lim n->oo (a_(n+1)/a_n) = c > 1, +oo The series diverge \n");
printf(" lim n->oo (a_(n+1)/a_n) = c = 1 Use another test \n\n");
stop();
clrscrn();
printf(" a_n : n-> %s \n", a_neq);
printf(" a_n+1 : n-> %s \n\n", a_npls1eq);
printf(" c_n : n-> a_n+1/a_n\n\n");
for(i=1; i<10; i++)
printf(" c_%.0f = %5.3f || \n", i, a_npls1(i)/a_n(i));
printf(" \n\n\n"
" lim n->oo (a_(n+1)/a_n) = c < 1 The series converge\n\n");
stop();
return 0;
}
/* ---------------------------------- */
/* ---------------------------------- */
Exemple de sortie écran :
The Ratio Test.
Let S.a_n be positive-term series.
lim n->oo (a_(n+1)/a_n) = c < 1 The series converge
lim n->oo (a_(n+1)/a_n) = c > 1, +oo The series diverge
lim n->oo (a_(n+1)/a_n) = c = 1 Use another test
Press return to continue.
Exemple de sortie écran :
a_n : n-> (1)/(n)!
a_n+1 : n-> (1)/(n+1)!
c_n : n-> a_n+1/a_n
c_1 = 0.500 ||
c_2 = 0.333 ||
c_3 = 0.250 ||
c_4 = 0.200 ||
c_5 = 0.167 ||
c_6 = 0.143 ||
c_7 = 0.125 ||
c_8 = 0.111 ||
c_9 = 0.100 ||
lim n->oo (a_(n+1)/a_n) = c < 1 The series converge
Press return to continue.