Mathc initiation/a568
Apparence
La méthode des fractions partielles. (5s+7) A B C ----------- = --- + ----- + ----- s(s+1)(s-2) s (s+1) (s-2) Multiplions par s(s+1)(s-2) les numérateurs : s(s+1)(s-2) (5s+7) A s(s+1)(s-2) B s(s+1)(s-2) C s(s+1)(s-2) ----------- ------ = ------------- + ------------- + ------------- s(s+1)(s-2) 1 s (s+1) (s-2) Simplifions : (5 s+7) = A (s+1)(s-2) + B s(s-2) + C s(s+1) Si s = (0) (5 (0) +7) = A ((0)+1)(0-2) + B (0)(s-2) + C (0)(s+1) 7 = A (+1)( -2) A = -7/2 Si s = (-1) (5 (-1)+7) = A ((-1)+1)((-1)-2) + B (-1)((-1)-2) + C (-1)((-1)+1) 2 = A (0) (-3) + B (-1) (-3) + C (-1) (0) 2 = 3 B B = 2/3 Si s = (2) (5 2+7) = A (s+1)(2-2) + B 2(2-2) + C 2(2+1) (17) = A (0) + B (0) + C (6) (17) = C 6 C = 17/6 Donc : (5 s + 7) A B C --------------- = --- + ------- + ------- s(s + 1)(s - 2) s (s + 1) (s - 2) (5 s + 7) 7/2 2/3 17/6 --------------- = - --- + ------- + ------- s(s + 1)(s - 2) s (s + 1) (s - 2)