Utilisateur:DavidL/Test5

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<ce>TEST 4+5/8</ce>
<math>TEST 4+5/8</math>

${\ce {TEST 4+5/8}}$

$TEST4+5/8$

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${\frac {\sqrt[{2}]{x}}{\sqrt[{3}]{x}}}={\sqrt[{6}]{x}}$	${\frac {\sqrt[{3}]{x}}{\sqrt[{4}]{x}}}={\sqrt[{12}]{x}}$	${\frac {\sqrt[{4}]{x}}{\sqrt[{5}]{x}}}={\sqrt[{20}]{x}}$	${\frac {\sqrt[{5}]{x}}{\sqrt[{6}]{x}}}={\sqrt[{30}]{x}}$	${\frac {\sqrt[{6}]{x}}{\sqrt[{7}]{x}}}={\sqrt[{42}]{x}}$	...
${\frac {1}{2}}-{\frac {1}{3}}={\frac {1}{6}}$	${\frac {1}{3}}-{\frac {1}{4}}={\frac {1}{12}}$	${\frac {1}{4}}-{\frac {1}{5}}={\frac {1}{20}}$	${\frac {1}{5}}-{\frac {1}{6}}={\frac {1}{30}}$	${\frac {1}{6}}-{\frac {1}{7}}={\frac {1}{42}}$	...

${\frac {\sqrt[{3}]{x}}{\sqrt[{5}]{x}}}\neq {\sqrt[{15}]{x}}$

${\frac {1}{3}}-{\frac {1}{5}}={\frac {2}{15}}$

${\frac {\sqrt[{3}]{x}}{\sqrt[{5}]{x}}}={\sqrt[{15}]{x^{2}}}$

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$\sum _{x=1}^{\infty }x=1+2+3+4+5+6+7+...$

$(\sum _{x=1}^{\infty }x)-1=2+3+4+5+6+7+...$

$\sum _{x=1}^{\infty }(x+1)=2+3+4+5+6+7+...$

$(\sum _{x=1}^{\infty }x)-1=\sum _{x=1}^{\infty }(x+1)$

$\sum _{x=1}^{\infty }x>\sum _{x=1}^{\infty }(x+1)$

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<math>

$C_{n}={2n \choose n}-{2n \choose n+1}\quad {\text{pour }}n\geq 0,$

<math display="block">

$$C_{n}={2n \choose n}-{2n \choose n+1}\quad {\text{pour }}n\geq 0,$$

<math display="inline">

${\textstyle C_{n}={2n \choose n}-{2n \choose n+1}\quad {\text{pour }}n\geq 0,}$

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$$\phi ={\sqrt {\frac {cos({\frac {\pi }{5}})\times (tan({\frac {\pi }{5}})+tan({\frac {\pi }{10}}))}{tan({\frac {\pi }{10}})}}}$$

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${\ce {2R3B\ +3CO\ +4H^{-}->[{\text{DG}}][{\text{45°}}]->[{\text{KOH}}]4ROH\ +2RCH2OH}}$

${\ce {2R3B\ +3CO\ +4H^{-}->[{\text{DG}}][{\text{45°}}]->[{\text{KOH}}]4ROH\ +2RCH2OH}}$

$2R3B\ +3CO\ +4H^{-}->[{\text{DG}}][{\text{45°}}]->[{\text{KOH}}]4ROH\ +2RCH2OH$